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5(2x-3)-8=3(x+4)
We move all terms to the left:
5(2x-3)-8-(3(x+4))=0
We multiply parentheses
10x-(3(x+4))-15-8=0
We calculate terms in parentheses: -(3(x+4)), so:We add all the numbers together, and all the variables
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
10x-(3x+12)-23=0
We get rid of parentheses
10x-3x-12-23=0
We add all the numbers together, and all the variables
7x-35=0
We move all terms containing x to the left, all other terms to the right
7x=35
x=35/7
x=5
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