5(2x-3)=(2x+x)(8-4)

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Solution for 5(2x-3)=(2x+x)(8-4) equation: 



5(2x-3)=(2x+x)(8-4)

We move all terms to the left:

5(2x-3)-((2x+x)(8-4))=0

We add all the numbers together, and all the variables

5(2x-3)-((+3x)4)=0

We multiply parentheses

10x-((+3x)4)-15=0



We calculate terms in parentheses: -((+3x)4), so:

(+3x)4

We multiply parentheses

12x

Back to the equation:

-(12x)



We add all the numbers together, and all the variables

-2x-15=0

We move all terms containing x to the left, all other terms to the right

-2x=15

x=15/-2

x=-7+1/2

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