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5(2x-3)=2(x-5)
We move all terms to the left:
5(2x-3)-(2(x-5))=0
We multiply parentheses
10x-(2(x-5))-15=0
We calculate terms in parentheses: -(2(x-5)), so:We get rid of parentheses
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
10x-2x+10-15=0
We add all the numbers together, and all the variables
8x-5=0
We move all terms containing x to the left, all other terms to the right
8x=5
x=5/8
x=5/8
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