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5(2x-3)=2-(2x-9)
We move all terms to the left:
5(2x-3)-(2-(2x-9))=0
We multiply parentheses
10x-(2-(2x-9))-15=0
We calculate terms in parentheses: -(2-(2x-9)), so:We get rid of parentheses
2-(2x-9)
determiningTheFunctionDomain -(2x-9)+2
We get rid of parentheses
-2x+9+2
We add all the numbers together, and all the variables
-2x+11
Back to the equation:
-(-2x+11)
10x+2x-11-15=0
We add all the numbers together, and all the variables
12x-26=0
We move all terms containing x to the left, all other terms to the right
12x=26
x=26/12
x=2+1/6
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