5(2x-3)=20x+35

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Solution for 5(2x-3)=20x+35 equation: 



5(2x-3)=20x+35

We move all terms to the left:

5(2x-3)-(20x+35)=0

We multiply parentheses

10x-(20x+35)-15=0

We get rid of parentheses

10x-20x-35-15=0

We add all the numbers together, and all the variables

-10x-50=0

We move all terms containing x to the left, all other terms to the right

-10x=50

x=50/-10

x=-5

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