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5(2x-3)=3(2x-4)
We move all terms to the left:
5(2x-3)-(3(2x-4))=0
We multiply parentheses
10x-(3(2x-4))-15=0
We calculate terms in parentheses: -(3(2x-4)), so:We get rid of parentheses
3(2x-4)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
10x-6x+12-15=0
We add all the numbers together, and all the variables
4x-3=0
We move all terms containing x to the left, all other terms to the right
4x=3
x=3/4
x=3/4
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