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5(2x-3)=3(5-3x)
We move all terms to the left:
5(2x-3)-(3(5-3x))=0
We add all the numbers together, and all the variables
5(2x-3)-(3(-3x+5))=0
We multiply parentheses
10x-(3(-3x+5))-15=0
We calculate terms in parentheses: -(3(-3x+5)), so:We get rid of parentheses
3(-3x+5)
We multiply parentheses
-9x+15
Back to the equation:
-(-9x+15)
10x+9x-15-15=0
We add all the numbers together, and all the variables
19x-30=0
We move all terms containing x to the left, all other terms to the right
19x=30
x=30/19
x=1+11/19
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