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5(2x-3)=3x+48
We move all terms to the left:
5(2x-3)-(3x+48)=0
We multiply parentheses
10x-(3x+48)-15=0
We get rid of parentheses
10x-3x-48-15=0
We add all the numbers together, and all the variables
7x-63=0
We move all terms containing x to the left, all other terms to the right
7x=63
x=63/7
x=9
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