5(2x-32)=2(x+40)

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Solution for 5(2x-32)=2(x+40) equation: 



5(2x-32)=2(x+40)

We move all terms to the left:

5(2x-32)-(2(x+40))=0

We multiply parentheses

10x-(2(x+40))-160=0



We calculate terms in parentheses: -(2(x+40)), so:

2(x+40)

We multiply parentheses

2x+80

Back to the equation:

-(2x+80)



We get rid of parentheses

10x-2x-80-160=0

We add all the numbers together, and all the variables

8x-240=0

We move all terms containing x to the left, all other terms to the right

8x=240

x=240/8

x=30

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