5(2x-4)(x+2)=0

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Solution for 5(2x-4)(x+2)=0 equation:


Simplifying
5(2x + -4)(x + 2) = 0

Reorder the terms:
5(-4 + 2x)(x + 2) = 0

Reorder the terms:
5(-4 + 2x)(2 + x) = 0

Multiply (-4 + 2x) * (2 + x)
5(-4(2 + x) + 2x * (2 + x)) = 0
5((2 * -4 + x * -4) + 2x * (2 + x)) = 0
5((-8 + -4x) + 2x * (2 + x)) = 0
5(-8 + -4x + (2 * 2x + x * 2x)) = 0
5(-8 + -4x + (4x + 2x2)) = 0

Combine like terms: -4x + 4x = 0
5(-8 + 0 + 2x2) = 0
5(-8 + 2x2) = 0
(-8 * 5 + 2x2 * 5) = 0
(-40 + 10x2) = 0

Solving
-40 + 10x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '40' to each side of the equation.
-40 + 40 + 10x2 = 0 + 40

Combine like terms: -40 + 40 = 0
0 + 10x2 = 0 + 40
10x2 = 0 + 40

Combine like terms: 0 + 40 = 40
10x2 = 40

Divide each side by '10'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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