5(2x-4)+2x+10=-3(x-5)+5x

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Solution for 5(2x-4)+2x+10=-3(x-5)+5x equation: 



5(2x-4)+2x+10=-3(x-5)+5x

We move all terms to the left:

5(2x-4)+2x+10-(-3(x-5)+5x)=0

We add all the numbers together, and all the variables

2x+5(2x-4)-(-3(x-5)+5x)+10=0

We multiply parentheses

2x+10x-(-3(x-5)+5x)-20+10=0



We calculate terms in parentheses: -(-3(x-5)+5x), so:

-3(x-5)+5x

We add all the numbers together, and all the variables

5x-3(x-5)

We multiply parentheses

5x-3x+15

We add all the numbers together, and all the variables

2x+15

Back to the equation:

-(2x+15)



We add all the numbers together, and all the variables

12x-(2x+15)-10=0

We get rid of parentheses

12x-2x-15-10=0

We add all the numbers together, and all the variables

10x-25=0

We move all terms containing x to the left, all other terms to the right

10x=25

x=25/10

x=2+1/2

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