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5(2x-4)+2x=5(2x-2)
We move all terms to the left:
5(2x-4)+2x-(5(2x-2))=0
We add all the numbers together, and all the variables
2x+5(2x-4)-(5(2x-2))=0
We multiply parentheses
2x+10x-(5(2x-2))-20=0
We calculate terms in parentheses: -(5(2x-2)), so:We add all the numbers together, and all the variables
5(2x-2)
We multiply parentheses
10x-10
Back to the equation:
-(10x-10)
12x-(10x-10)-20=0
We get rid of parentheses
12x-10x+10-20=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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