5(2x-4)-(6x+4)-3(x-8)=2x-(1-x)-19

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Solution for 5(2x-4)-(6x+4)-3(x-8)=2x-(1-x)-19 equation:



5(2x-4)-(6x+4)-3(x-8)=2x-(1-x)-19
We move all terms to the left:
5(2x-4)-(6x+4)-3(x-8)-(2x-(1-x)-19)=0
We add all the numbers together, and all the variables
5(2x-4)-(6x+4)-3(x-8)-(2x-(-1x+1)-19)=0
We multiply parentheses
10x-(6x+4)-3x-(2x-(-1x+1)-19)-20+24=0
We get rid of parentheses
10x-6x-3x-(2x-(-1x+1)-19)-4-20+24=0
We calculate terms in parentheses: -(2x-(-1x+1)-19), so:
2x-(-1x+1)-19
We get rid of parentheses
2x+1x-1-19
We add all the numbers together, and all the variables
3x-20
Back to the equation:
-(3x-20)
We add all the numbers together, and all the variables
x-(3x-20)=0
We get rid of parentheses
x-3x+20=0
We add all the numbers together, and all the variables
-2x+20=0
We move all terms containing x to the left, all other terms to the right
-2x=-20
x=-20/-2
x=+10

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