5(2x-4)-2=5(x-5)+48

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Solution for 5(2x-4)-2=5(x-5)+48 equation: 



5(2x-4)-2=5(x-5)+48

We move all terms to the left:

5(2x-4)-2-(5(x-5)+48)=0

We multiply parentheses

10x-(5(x-5)+48)-20-2=0



We calculate terms in parentheses: -(5(x-5)+48), so:

5(x-5)+48

We multiply parentheses

5x-25+48

We add all the numbers together, and all the variables

5x+23

Back to the equation:

-(5x+23)



We add all the numbers together, and all the variables

10x-(5x+23)-22=0

We get rid of parentheses

10x-5x-23-22=0

We add all the numbers together, and all the variables

5x-45=0

We move all terms containing x to the left, all other terms to the right

5x=45

x=45/5

x=9

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