5(2x-4)=12-(3-2x)

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Solution for 5(2x-4)=12-(3-2x) equation: 



5(2x-4)=12-(3-2x)

We move all terms to the left:

5(2x-4)-(12-(3-2x))=0

We add all the numbers together, and all the variables

5(2x-4)-(12-(-2x+3))=0

We multiply parentheses

10x-(12-(-2x+3))-20=0



We calculate terms in parentheses: -(12-(-2x+3)), so:

12-(-2x+3)

determiningTheFunctionDomain
-(-2x+3)+12

We get rid of parentheses

2x-3+12

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We get rid of parentheses

10x-2x-9-20=0

We add all the numbers together, and all the variables

8x-29=0

We move all terms containing x to the left, all other terms to the right

8x=29

x=29/8

x=3+5/8

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