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5(2x-4)=2(10-5x)
We move all terms to the left:
5(2x-4)-(2(10-5x))=0
We add all the numbers together, and all the variables
5(2x-4)-(2(-5x+10))=0
We multiply parentheses
10x-(2(-5x+10))-20=0
We calculate terms in parentheses: -(2(-5x+10)), so:We get rid of parentheses
2(-5x+10)
We multiply parentheses
-10x+20
Back to the equation:
-(-10x+20)
10x+10x-20-20=0
We add all the numbers together, and all the variables
20x-40=0
We move all terms containing x to the left, all other terms to the right
20x=40
x=40/20
x=2
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