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5(2x-4)=2(3x+10)
We move all terms to the left:
5(2x-4)-(2(3x+10))=0
We multiply parentheses
10x-(2(3x+10))-20=0
We calculate terms in parentheses: -(2(3x+10)), so:We get rid of parentheses
2(3x+10)
We multiply parentheses
6x+20
Back to the equation:
-(6x+20)
10x-6x-20-20=0
We add all the numbers together, and all the variables
4x-40=0
We move all terms containing x to the left, all other terms to the right
4x=40
x=40/4
x=10
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