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5(2x-4)=2(3x-5)
We move all terms to the left:
5(2x-4)-(2(3x-5))=0
We multiply parentheses
10x-(2(3x-5))-20=0
We calculate terms in parentheses: -(2(3x-5)), so:We get rid of parentheses
2(3x-5)
We multiply parentheses
6x-10
Back to the equation:
-(6x-10)
10x-6x+10-20=0
We add all the numbers together, and all the variables
4x-10=0
We move all terms containing x to the left, all other terms to the right
4x=10
x=10/4
x=2+1/2
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