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5(2x-4)=3(2x+1)-1
We move all terms to the left:
5(2x-4)-(3(2x+1)-1)=0
We multiply parentheses
10x-(3(2x+1)-1)-20=0
We calculate terms in parentheses: -(3(2x+1)-1), so:We get rid of parentheses
3(2x+1)-1
We multiply parentheses
6x+3-1
We add all the numbers together, and all the variables
6x+2
Back to the equation:
-(6x+2)
10x-6x-2-20=0
We add all the numbers together, and all the variables
4x-22=0
We move all terms containing x to the left, all other terms to the right
4x=22
x=22/4
x=5+1/2
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