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5(2x-4)=3(2x-1)=1
We move all terms to the left:
5(2x-4)-(3(2x-1))=0
We multiply parentheses
10x-(3(2x-1))-20=0
We calculate terms in parentheses: -(3(2x-1)), so:We get rid of parentheses
3(2x-1)
We multiply parentheses
6x-3
Back to the equation:
-(6x-3)
10x-6x+3-20=0
We add all the numbers together, and all the variables
4x-17=0
We move all terms containing x to the left, all other terms to the right
4x=17
x=17/4
x=4+1/4
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