5(2x-4)=3(3x-6)+x-2=

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Solution for 5(2x-4)=3(3x-6)+x-2= equation: 



5(2x-4)=3(3x-6)+x-2=

We move all terms to the left:

5(2x-4)-(3(3x-6)+x-2)=0

We multiply parentheses

10x-(3(3x-6)+x-2)-20=0



We calculate terms in parentheses: -(3(3x-6)+x-2), so:

3(3x-6)+x-2

We add all the numbers together, and all the variables

x+3(3x-6)-2

We multiply parentheses

x+9x-18-2

We add all the numbers together, and all the variables

10x-20

Back to the equation:

-(10x-20)



We get rid of parentheses

10x-10x+20-20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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