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5(2x-4)=3(3x-6)+x-2=-
We move all terms to the left:
5(2x-4)-(3(3x-6)+x-2)=0
We multiply parentheses
10x-(3(3x-6)+x-2)-20=0
We calculate terms in parentheses: -(3(3x-6)+x-2), so:We get rid of parentheses
3(3x-6)+x-2
We add all the numbers together, and all the variables
x+3(3x-6)-2
We multiply parentheses
x+9x-18-2
We add all the numbers together, and all the variables
10x-20
Back to the equation:
-(10x-20)
10x-10x+20-20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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