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5(2x-4)=3-4(x-2)
We move all terms to the left:
5(2x-4)-(3-4(x-2))=0
We multiply parentheses
10x-(3-4(x-2))-20=0
We calculate terms in parentheses: -(3-4(x-2)), so:We get rid of parentheses
3-4(x-2)
determiningTheFunctionDomain -4(x-2)+3
We multiply parentheses
-4x+8+3
We add all the numbers together, and all the variables
-4x+11
Back to the equation:
-(-4x+11)
10x+4x-11-20=0
We add all the numbers together, and all the variables
14x-31=0
We move all terms containing x to the left, all other terms to the right
14x=31
x=31/14
x=2+3/14
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