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5(2x-4+3x)=5(2x+4+3x)
We move all terms to the left:
5(2x-4+3x)-(5(2x+4+3x))=0
We add all the numbers together, and all the variables
5(5x-4)-(5(5x+4))=0
We multiply parentheses
25x-(5(5x+4))-20=0
We calculate terms in parentheses: -(5(5x+4)), so:We get rid of parentheses
5(5x+4)
We multiply parentheses
25x+20
Back to the equation:
-(25x+20)
25x-25x-20-20=0
We add all the numbers together, and all the variables
-40!=0
There is no solution for this equation
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