5(2x-5)+2(x-3)=4(x-1)

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Solution for 5(2x-5)+2(x-3)=4(x-1) equation: 



5(2x-5)+2(x-3)=4(x-1)

We move all terms to the left:

5(2x-5)+2(x-3)-(4(x-1))=0

We multiply parentheses

10x+2x-(4(x-1))-25-6=0



We calculate terms in parentheses: -(4(x-1)), so:

4(x-1)

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

12x-(4x-4)-31=0

We get rid of parentheses

12x-4x+4-31=0

We add all the numbers together, and all the variables

8x-27=0

We move all terms containing x to the left, all other terms to the right

8x=27

x=27/8

x=3+3/8

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