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5(2x-5)-3=4x-(6x-1)
We move all terms to the left:
5(2x-5)-3-(4x-(6x-1))=0
We multiply parentheses
10x-(4x-(6x-1))-25-3=0
We calculate terms in parentheses: -(4x-(6x-1)), so:We add all the numbers together, and all the variables
4x-(6x-1)
We get rid of parentheses
4x-6x+1
We add all the numbers together, and all the variables
-2x+1
Back to the equation:
-(-2x+1)
10x-(-2x+1)-28=0
We get rid of parentheses
10x+2x-1-28=0
We add all the numbers together, and all the variables
12x-29=0
We move all terms containing x to the left, all other terms to the right
12x=29
x=29/12
x=2+5/12
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