5(2x-5)-4=5(x-3)+11

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Solution for 5(2x-5)-4=5(x-3)+11 equation: 



5(2x-5)-4=5(x-3)+11

We move all terms to the left:

5(2x-5)-4-(5(x-3)+11)=0

We multiply parentheses

10x-(5(x-3)+11)-25-4=0



We calculate terms in parentheses: -(5(x-3)+11), so:

5(x-3)+11

We multiply parentheses

5x-15+11

We add all the numbers together, and all the variables

5x-4

Back to the equation:

-(5x-4)



We add all the numbers together, and all the variables

10x-(5x-4)-29=0

We get rid of parentheses

10x-5x+4-29=0

We add all the numbers together, and all the variables

5x-25=0

We move all terms containing x to the left, all other terms to the right

5x=25

x=25/5

x=5

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