5(2x-5)-4=5(x-3)+21

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Solution for 5(2x-5)-4=5(x-3)+21 equation: 



5(2x-5)-4=5(x-3)+21

We move all terms to the left:

5(2x-5)-4-(5(x-3)+21)=0

We multiply parentheses

10x-(5(x-3)+21)-25-4=0



We calculate terms in parentheses: -(5(x-3)+21), so:

5(x-3)+21

We multiply parentheses

5x-15+21

We add all the numbers together, and all the variables

5x+6

Back to the equation:

-(5x+6)



We add all the numbers together, and all the variables

10x-(5x+6)-29=0

We get rid of parentheses

10x-5x-6-29=0

We add all the numbers together, and all the variables

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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