5(2x-5)=(18x+40)

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Solution for 5(2x-5)=(18x+40) equation: 



5(2x-5)=(18x+40)

We move all terms to the left:

5(2x-5)-((18x+40))=0

We multiply parentheses

10x-((18x+40))-25=0



We calculate terms in parentheses: -((18x+40)), so:

(18x+40)

We get rid of parentheses

18x+40

Back to the equation:

-(18x+40)



We get rid of parentheses

10x-18x-40-25=0

We add all the numbers together, and all the variables

-8x-65=0

We move all terms containing x to the left, all other terms to the right

-8x=65

x=65/-8

x=-8+1/8

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