5(2x-5)=1/2(18x+40)

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Solution for 5(2x-5)=1/2(18x+40) equation: 



5(2x-5)=1/2(18x+40)

We move all terms to the left:

5(2x-5)-(1/2(18x+40))=0



Domain of the equation: 2(18x+40))!=0

x∈R



We multiply parentheses

10x-(1/2(18x+40))-25=0

We multiply all the terms by the denominator


10x*2(18x+40))-(1-25*2(18x+40))=0

Wy multiply elements

20x^2(1-50x(1=0

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