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5(2x-7)-5=5(x-2)+5
We move all terms to the left:
5(2x-7)-5-(5(x-2)+5)=0
We multiply parentheses
10x-(5(x-2)+5)-35-5=0
We calculate terms in parentheses: -(5(x-2)+5), so:We add all the numbers together, and all the variables
5(x-2)+5
We multiply parentheses
5x-10+5
We add all the numbers together, and all the variables
5x-5
Back to the equation:
-(5x-5)
10x-(5x-5)-40=0
We get rid of parentheses
10x-5x+5-40=0
We add all the numbers together, and all the variables
5x-35=0
We move all terms containing x to the left, all other terms to the right
5x=35
x=35/5
x=7
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