5(2x-7)-8=5(x-3)+7

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Solution for 5(2x-7)-8=5(x-3)+7 equation: 



5(2x-7)-8=5(x-3)+7

We move all terms to the left:

5(2x-7)-8-(5(x-3)+7)=0

We multiply parentheses

10x-(5(x-3)+7)-35-8=0



We calculate terms in parentheses: -(5(x-3)+7), so:

5(x-3)+7

We multiply parentheses

5x-15+7

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We add all the numbers together, and all the variables

10x-(5x-8)-43=0

We get rid of parentheses

10x-5x+8-43=0

We add all the numbers together, and all the variables

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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