5(2x-8)-7=5(x-4)+8

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Solution for 5(2x-8)-7=5(x-4)+8 equation: 



5(2x-8)-7=5(x-4)+8

We move all terms to the left:

5(2x-8)-7-(5(x-4)+8)=0

We multiply parentheses

10x-(5(x-4)+8)-40-7=0



We calculate terms in parentheses: -(5(x-4)+8), so:

5(x-4)+8

We multiply parentheses

5x-20+8

We add all the numbers together, and all the variables

5x-12

Back to the equation:

-(5x-12)



We add all the numbers together, and all the variables

10x-(5x-12)-47=0

We get rid of parentheses

10x-5x+12-47=0

We add all the numbers together, and all the variables

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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