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5(2x-8)6x=2x+4
We move all terms to the left:
5(2x-8)6x-(2x+4)=0
We multiply parentheses
60x^2-240x-(2x+4)=0
We get rid of parentheses
60x^2-240x-2x-4=0
We add all the numbers together, and all the variables
60x^2-242x-4=0
a = 60; b = -242; c = -4;
Δ = b2-4ac
Δ = -2422-4·60·(-4)
Δ = 59524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{59524}=\sqrt{4*14881}=\sqrt{4}*\sqrt{14881}=2\sqrt{14881}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-242)-2\sqrt{14881}}{2*60}=\frac{242-2\sqrt{14881}}{120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-242)+2\sqrt{14881}}{2*60}=\frac{242+2\sqrt{14881}}{120} $
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