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5(2x-8)=5(2x+1)
We move all terms to the left:
5(2x-8)-(5(2x+1))=0
We multiply parentheses
10x-(5(2x+1))-40=0
We calculate terms in parentheses: -(5(2x+1)), so:We get rid of parentheses
5(2x+1)
We multiply parentheses
10x+5
Back to the equation:
-(10x+5)
10x-10x-5-40=0
We add all the numbers together, and all the variables
-45!=0
There is no solution for this equation
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