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5(2x-9)+1/4(-16x-8)=1
We move all terms to the left:
5(2x-9)+1/4(-16x-8)-(1)=0
Domain of the equation: 4(-16x-8)!=0We multiply parentheses
x∈R
10x+1/4(-16x-8)-45-1=0
We multiply all the terms by the denominator
10x*4(-16x-8)-45*4(-16x-8)-1*4(-16x-8)+1=0
Wy multiply elements
40x^2(--180x(--4x(-+1=0
We use the square of the difference formula
40x^2(+180x(+4x(-1=0
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