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5(2x-9)-4=5(x-3)+1
We move all terms to the left:
5(2x-9)-4-(5(x-3)+1)=0
We multiply parentheses
10x-(5(x-3)+1)-45-4=0
We calculate terms in parentheses: -(5(x-3)+1), so:We add all the numbers together, and all the variables
5(x-3)+1
We multiply parentheses
5x-15+1
We add all the numbers together, and all the variables
5x-14
Back to the equation:
-(5x-14)
10x-(5x-14)-49=0
We get rid of parentheses
10x-5x+14-49=0
We add all the numbers together, and all the variables
5x-35=0
We move all terms containing x to the left, all other terms to the right
5x=35
x=35/5
x=7
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