5(2y+1)=3(y-3)

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Solution for 5(2y+1)=3(y-3) equation: 



5(2y+1)=3(y-3)

We move all terms to the left:

5(2y+1)-(3(y-3))=0

We multiply parentheses

10y-(3(y-3))+5=0



We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)



We get rid of parentheses

10y-3y+9+5=0

We add all the numbers together, and all the variables

7y+14=0

We move all terms containing y to the left, all other terms to the right

7y=-14

y=-14/7

y=-2

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