5(2y+1)=35

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Solution for 5(2y+1)=35 equation: 



5(2y+1)=35

We move all terms to the left:

5(2y+1)-(35)=0

We multiply parentheses

10y+5-35=0

We add all the numbers together, and all the variables

10y-30=0

We move all terms containing y to the left, all other terms to the right

10y=30

y=30/10

y=3

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