5(2y+1)=4y+1

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Solution for 5(2y+1)=4y+1 equation: 



5(2y+1)=4y+1

We move all terms to the left:

5(2y+1)-(4y+1)=0

We multiply parentheses

10y-(4y+1)+5=0

We get rid of parentheses

10y-4y-1+5=0

We add all the numbers together, and all the variables

6y+4=0

We move all terms containing y to the left, all other terms to the right

6y=-4

y=-4/6

y=-2/3

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