5(2y+2/3)+4y=1

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Solution for 5(2y+2/3)+4y=1 equation:



5(2y+2/3)+4y=1
We move all terms to the left:
5(2y+2/3)+4y-(1)=0
We add all the numbers together, and all the variables
5(+2y+2/3)+4y-1=0
We add all the numbers together, and all the variables
4y+5(+2y+2/3)-1=0
We multiply parentheses
4y+10y-1+2/3*5=0
We multiply all the terms by the denominator
4y*3*5+10y*3*5+2-1*3*5=0
We add all the numbers together, and all the variables
4y*3*5+10y*3*5-13=0
Wy multiply elements
60y*5+150y*5-13=0
Wy multiply elements
300y+750y-13=0
We add all the numbers together, and all the variables
1050y-13=0
We move all terms containing y to the left, all other terms to the right
1050y=13
y=13/1050
y=13/1050

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