5(2y+3)+10=4(5y-4)+18

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Solution for 5(2y+3)+10=4(5y-4)+18 equation:



5(2y+3)+10=4(5y-4)+18
We move all terms to the left:
5(2y+3)+10-(4(5y-4)+18)=0
We multiply parentheses
10y-(4(5y-4)+18)+15+10=0
We calculate terms in parentheses: -(4(5y-4)+18), so:
4(5y-4)+18
We multiply parentheses
20y-16+18
We add all the numbers together, and all the variables
20y+2
Back to the equation:
-(20y+2)
We add all the numbers together, and all the variables
10y-(20y+2)+25=0
We get rid of parentheses
10y-20y-2+25=0
We add all the numbers together, and all the variables
-10y+23=0
We move all terms containing y to the left, all other terms to the right
-10y=-23
y=-23/-10
y=2+3/10

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