5(2y+3)+3=(4y-1)

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Solution for 5(2y+3)+3=(4y-1) equation: 



5(2y+3)+3=(4y-1)

We move all terms to the left:

5(2y+3)+3-((4y-1))=0

We multiply parentheses

10y-((4y-1))+15+3=0



We calculate terms in parentheses: -((4y-1)), so:

(4y-1)

We get rid of parentheses

4y-1

Back to the equation:

-(4y-1)



We add all the numbers together, and all the variables

10y-(4y-1)+18=0

We get rid of parentheses

10y-4y+1+18=0

We add all the numbers together, and all the variables

6y+19=0

We move all terms containing y to the left, all other terms to the right

6y=-19

y=-19/6

y=-3+1/6

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