5(2y+3)-4y=2y-1

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Solution for 5(2y+3)-4y=2y-1 equation: 



5(2y+3)-4y=2y-1

We move all terms to the left:

5(2y+3)-4y-(2y-1)=0

We add all the numbers together, and all the variables

-4y+5(2y+3)-(2y-1)=0

We multiply parentheses

-4y+10y-(2y-1)+15=0

We get rid of parentheses

-4y+10y-2y+1+15=0

We add all the numbers together, and all the variables

4y+16=0

We move all terms containing y to the left, all other terms to the right

4y=-16

y=-16/4

y=-4

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