5(2y+4)-5=3+3(2y-4)

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Solution for 5(2y+4)-5=3+3(2y-4) equation: 



5(2y+4)-5=3+3(2y-4)

We move all terms to the left:

5(2y+4)-5-(3+3(2y-4))=0

We multiply parentheses

10y-(3+3(2y-4))+20-5=0



We calculate terms in parentheses: -(3+3(2y-4)), so:

3+3(2y-4)

determiningTheFunctionDomain
3(2y-4)+3

We multiply parentheses

6y-12+3

We add all the numbers together, and all the variables

6y-9

Back to the equation:

-(6y-9)



We add all the numbers together, and all the variables

10y-(6y-9)+15=0

We get rid of parentheses

10y-6y+9+15=0

We add all the numbers together, and all the variables

4y+24=0

We move all terms containing y to the left, all other terms to the right

4y=-24

y=-24/4

y=-6

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