5(2y+4)=8-3(y-4)

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Solution for 5(2y+4)=8-3(y-4) equation: 



5(2y+4)=8-3(y-4)

We move all terms to the left:

5(2y+4)-(8-3(y-4))=0

We multiply parentheses

10y-(8-3(y-4))+20=0



We calculate terms in parentheses: -(8-3(y-4)), so:

8-3(y-4)

determiningTheFunctionDomain
-3(y-4)+8

We multiply parentheses

-3y+12+8

We add all the numbers together, and all the variables

-3y+20

Back to the equation:

-(-3y+20)



We get rid of parentheses

10y+3y-20+20=0

We add all the numbers together, and all the variables

13y=0

y=0/13

y=0

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