5(2y+6)=-4(-5-2y)+3+3y

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Solution for 5(2y+6)=-4(-5-2y)+3+3y equation:



5(2y+6)=-4(-5-2y)+3+3y
We move all terms to the left:
5(2y+6)-(-4(-5-2y)+3+3y)=0
We add all the numbers together, and all the variables
5(2y+6)-(-4(-2y-5)+3+3y)=0
We multiply parentheses
10y-(-4(-2y-5)+3+3y)+30=0
We calculate terms in parentheses: -(-4(-2y-5)+3+3y), so:
-4(-2y-5)+3+3y
determiningTheFunctionDomain -4(-2y-5)+3y+3
We add all the numbers together, and all the variables
3y-4(-2y-5)+3
We multiply parentheses
3y+8y+20+3
We add all the numbers together, and all the variables
11y+23
Back to the equation:
-(11y+23)
We get rid of parentheses
10y-11y-23+30=0
We add all the numbers together, and all the variables
-1y+7=0
We move all terms containing y to the left, all other terms to the right
-y=-7
y=-7/-1
y=+7

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