5(2y+7)=3(4y-5)=

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Solution for 5(2y+7)=3(4y-5)= equation: 



5(2y+7)=3(4y-5)=

We move all terms to the left:

5(2y+7)-(3(4y-5))=0

We multiply parentheses

10y-(3(4y-5))+35=0



We calculate terms in parentheses: -(3(4y-5)), so:

3(4y-5)

We multiply parentheses

12y-15

Back to the equation:

-(12y-15)



We get rid of parentheses

10y-12y+15+35=0

We add all the numbers together, and all the variables

-2y+50=0

We move all terms containing y to the left, all other terms to the right

-2y=-50

y=-50/-2

y=+25

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