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5(2y+7)=3(y-5)
We move all terms to the left:
5(2y+7)-(3(y-5))=0
We multiply parentheses
10y-(3(y-5))+35=0
We calculate terms in parentheses: -(3(y-5)), so:We get rid of parentheses
3(y-5)
We multiply parentheses
3y-15
Back to the equation:
-(3y-15)
10y-3y+15+35=0
We add all the numbers together, and all the variables
7y+50=0
We move all terms containing y to the left, all other terms to the right
7y=-50
y=-50/7
y=-7+1/7
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