5(2y-1)+0.4(6y+1)=4(y+2)

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Solution for 5(2y-1)+0.4(6y+1)=4(y+2) equation: 



5(2y-1)+0.4(6y+1)=4(y+2)

We move all terms to the left:

5(2y-1)+0.4(6y+1)-(4(y+2))=0

We multiply parentheses

10y+2.4y-(4(y+2))-5+0.4=0



We calculate terms in parentheses: -(4(y+2)), so:

4(y+2)

We multiply parentheses

4y+8

Back to the equation:

-(4y+8)



We add all the numbers together, and all the variables

12.4y-(4y+8)-4.6=0

We get rid of parentheses

12.4y-4y-8-4.6=0

We add all the numbers together, and all the variables

8.4y-12.6=0

We move all terms containing y to the left, all other terms to the right

8.4y=12.6

y=12.6/8.4

y=1+1/2

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